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y-2=1/5(3y-1)
We move all terms to the left:
y-2-(1/5(3y-1))=0
Domain of the equation: 5(3y-1))!=0We multiply all the terms by the denominator
y∈R
y*5(3y-1))-(1-2*5(3y-1))=0
Wy multiply elements
5y^2(3-10y(3=0
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