y-2(3y+1)=4(y-4)

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Solution for y-2(3y+1)=4(y-4) equation: 



y-2(3y+1)=4(y-4)

We move all terms to the left:

y-2(3y+1)-(4(y-4))=0

We multiply parentheses

y-6y-(4(y-4))-2=0



We calculate terms in parentheses: -(4(y-4)), so:

4(y-4)

We multiply parentheses

4y-16

Back to the equation:

-(4y-16)



We add all the numbers together, and all the variables

-5y-(4y-16)-2=0

We get rid of parentheses

-5y-4y+16-2=0

We add all the numbers together, and all the variables

-9y+14=0

We move all terms containing y to the left, all other terms to the right

-9y=-14

y=-14/-9

y=1+5/9

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