y-(3y-2y-5/10)=1/6(2y-57)

Solution for y-(3y-2y-5/10)=1/6(2y-57) equation:

y-(3y-2y-5/10)=1/6(2y-57)

We move all terms to the left:

y-(3y-2y-5/10)-(1/6(2y-57))=0


Domain of the equation: 6(2y-57))!=0

y∈R


We add all the numbers together, and all the variables

y-(+y-5/10)-(1/6(2y-57))=0

We get rid of parentheses

y-y-(1/6(2y-57))+5/10=0

We calculate fractions


y-y+()/120y+(30y2/120y=0

We add all the numbers together, and all the variables

()/120y+(30y2/120y=0

We multiply all the terms by the denominator


(30y2+()=0


We calculate terms in parentheses: +(30y2+(), so:

30y2+(

We add all the numbers together, and all the variables

30y^2

Back to the equation:

+(30y^2)


a = 30; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·30·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{60}=0$