y+7/15=1+(3y-2)/5

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Solution for y+7/15=1+(3y-2)/5 equation: 



y+7/15=1+(3y-2)/5

We move all terms to the left:

y+7/15-(1+(3y-2)/5)=0

We calculate fractions


y+(-(1+(3y-2)*15)/()+()/()=0



We calculate terms in parentheses: +(-(1+(3y-2)*15)/()+()/(), so:

-(1+(3y-2)*15)/()+()/(

We add all the numbers together, and all the variables

-(1+(3y-2)*15)/()+1

We multiply all the terms by the denominator


-(1+(3y-2)*15)+1*()



We calculate terms in parentheses: -(1+(3y-2)*15), so:

1+(3y-2)*15

determiningTheFunctionDomain
(3y-2)*15+1

We multiply parentheses

45y-30+1

We add all the numbers together, and all the variables

45y-29

Back to the equation:

-(45y-29)



We add all the numbers together, and all the variables

-(45y-29)

We get rid of parentheses

-45y+29

Back to the equation:

+(-45y+29)



We get rid of parentheses

y-45y+29=0

We add all the numbers together, and all the variables

-44y+29=0

We move all terms containing y to the left, all other terms to the right

-44y=-29

y=-29/-44

y=29/44

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