y+4/3y+8=1

Solution for y+4/3y+8=1 equation:

y+4/3y+8=1

We move all terms to the left:

y+4/3y+8-(1)=0


Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R


We add all the numbers together, and all the variables

y+4/3y+7=0

We multiply all the terms by the denominator


y*3y+7*3y+4=0

Wy multiply elements

3y^2+21y+4=0

a = 3; b = 21; c = +4;
Δ = b2-4ac
Δ = 212-4·3·4
Δ = 393
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{393}}{2*3}=\frac{-21-\sqrt{393}}{6}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{393}}{2*3}=\frac{-21+\sqrt{393}}{6}
$