y+4(5y+3)=12(y+1)+7y

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Solution for y+4(5y+3)=12(y+1)+7y equation:


Simplifying
y + 4(5y + 3) = 12(y + 1) + 7y

Reorder the terms:
y + 4(3 + 5y) = 12(y + 1) + 7y
y + (3 * 4 + 5y * 4) = 12(y + 1) + 7y
y + (12 + 20y) = 12(y + 1) + 7y

Reorder the terms:
12 + y + 20y = 12(y + 1) + 7y

Combine like terms: y + 20y = 21y
12 + 21y = 12(y + 1) + 7y

Reorder the terms:
12 + 21y = 12(1 + y) + 7y
12 + 21y = (1 * 12 + y * 12) + 7y
12 + 21y = (12 + 12y) + 7y

Combine like terms: 12y + 7y = 19y
12 + 21y = 12 + 19y

Add '-12' to each side of the equation.
12 + -12 + 21y = 12 + -12 + 19y

Combine like terms: 12 + -12 = 0
0 + 21y = 12 + -12 + 19y
21y = 12 + -12 + 19y

Combine like terms: 12 + -12 = 0
21y = 0 + 19y
21y = 19y

Solving
21y = 19y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-19y' to each side of the equation.
21y + -19y = 19y + -19y

Combine like terms: 21y + -19y = 2y
2y = 19y + -19y

Combine like terms: 19y + -19y = 0
2y = 0

Divide each side by '2'.
y = 0

Simplifying
y = 0

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