y+4(2y+1)=8+(2y-1)

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Solution for y+4(2y+1)=8+(2y-1) equation: 



y+4(2y+1)=8+(2y-1)

We move all terms to the left:

y+4(2y+1)-(8+(2y-1))=0

We multiply parentheses

y+8y-(8+(2y-1))+4=0



We calculate terms in parentheses: -(8+(2y-1)), so:

8+(2y-1)

determiningTheFunctionDomain
(2y-1)+8

We get rid of parentheses

2y-1+8

We add all the numbers together, and all the variables

2y+7

Back to the equation:

-(2y+7)



We add all the numbers together, and all the variables

9y-(2y+7)+4=0

We get rid of parentheses

9y-2y-7+4=0

We add all the numbers together, and all the variables

7y-3=0

We move all terms containing y to the left, all other terms to the right

7y=3

y=3/7

y=3/7

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