y+2(y-8)=6y-4(y-10)

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Solution for y+2(y-8)=6y-4(y-10) equation: 



y+2(y-8)=6y-4(y-10)

We move all terms to the left:

y+2(y-8)-(6y-4(y-10))=0

We multiply parentheses

y+2y-(6y-4(y-10))-16=0



We calculate terms in parentheses: -(6y-4(y-10)), so:

6y-4(y-10)

We multiply parentheses

6y-4y+40

We add all the numbers together, and all the variables

2y+40

Back to the equation:

-(2y+40)



We add all the numbers together, and all the variables

3y-(2y+40)-16=0

We get rid of parentheses

3y-2y-40-16=0

We add all the numbers together, and all the variables

y-56=0

We move all terms containing y to the left, all other terms to the right

y=56

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