y+2(y+3(y+4(y+1/24)))=100

Solution for y+2(y+3(y+4(y+1/24)))=100 equation:

y+2(y+3(y+4(y+1/24)))=100

We move all terms to the left:

y+2(y+3(y+4(y+1/24)))-(100)=0

We add all the numbers together, and all the variables

y+2(y+3(y+4(+y+1/24)))-100=0

We multiply all the terms by the denominator


y*24)))+2(y+3(y+4(+y+1-100*24)))=0

We add all the numbers together, and all the variables

y*24)))+2(y+3(y+4(y-2399)))=0

We add all the numbers together, and all the variables

y*24)))+2(y+3(y+4(y=0

Wy multiply elements

24y^2=0

a = 24; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·24·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{48}=0$