y+1=(5-y)/2

Solution for y+1=(5-y)/2 equation:

y+1=(5-y)/2

We move all terms to the left:

y+1-((5-y)/2)=0

We add all the numbers together, and all the variables

y-((-1y+5)/2)+1=0

We multiply all the terms by the denominator


y*2)-((-1y+5)+1*2)=0

We add all the numbers together, and all the variables

y*2)-((-1y+5)=0

Wy multiply elements

2y^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{4}=0$