y+13=17/y=4

Solution for y+13=17/y=4 equation:

y+13=17/y=4

We move all terms to the left:

y+13-(17/y)=0


Domain of the equation: y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

y-(+17/y)+13=0

We get rid of parentheses

y-17/y+13=0

We multiply all the terms by the denominator


y*y+13*y-17=0

We add all the numbers together, and all the variables

13y+y*y-17=0

Wy multiply elements

y^2+13y-17=0

a = 1; b = 13; c = -17;
Δ = b2-4ac
Δ = 132-4·1·(-17)
Δ = 237
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{237}}{2*1}=\frac{-13-\sqrt{237}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{237}}{2*1}=\frac{-13+\sqrt{237}}{2}
$