y+1/y+6-y/y2-36=y-3/y-6

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Solution for y+1/y+6-y/y2-36=y-3/y-6 equation: 


D( y )

y = 0

y^2 = 0

y = 0

y = 0

y^2 = 0

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in (-oo:0) U (0:+oo)

y+1/y-(y/(y^2))-36+6 = y-(3/y)-6 // - y-(3/y)-6

y-y+1/y-(y/(y^2))+3/y-36+6+6 = 0

y-y+1/y-y^-1+3/y-36+6+6 = 0

3*y^-1 = 24 // : 3

y^-1 = 8

-1 < 0

1/(y^1) = 8 // * y^1

1 = 8*y^1 // : 8

1/8 = y^1

y = 1/8

y = 1/8

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