y+1-2(-2)=y+3-(1-y)

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Solution for y+1-2(-2)=y+3-(1-y) equation: 



y+1-2(-2)=y+3-(1-y)

We move all terms to the left:

y+1-2(-2)-(y+3-(1-y))=0

We add all the numbers together, and all the variables

y-(y+3-(-1y+1))+1-2(-2)=0

We add all the numbers together, and all the variables

y-(y+3-(-1y+1))+5=0



We calculate terms in parentheses: -(y+3-(-1y+1)), so:

y+3-(-1y+1)

determiningTheFunctionDomain
y-(-1y+1)+3

We get rid of parentheses

y+1y-1+3

We add all the numbers together, and all the variables

2y+2

Back to the equation:

-(2y+2)



We get rid of parentheses

y-2y-2+5=0

We add all the numbers together, and all the variables

-1y+3=0

We move all terms containing y to the left, all other terms to the right

-y=-3

y=-3/-1

y=+3

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