y(y-12)+y-12=0

Solution for y(y-12)+y-12=0 equation:

Simplifying
y(y + -12) + y + -12 = 0

Reorder the terms:
y(-12 + y) + y + -12 = 0
(-12 * y + y * y) + y + -12 = 0
(-12y + y2) + y + -12 = 0

Reorder the terms:
-12 + -12y + y + y2 = 0

Combine like terms: -12y + y = -11y
-12 + -11y + y2 = 0

Solving
-12 + -11y + y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-1 + -1y)(12 + -1y) = 0

Subproblem 1
Set the factor '(-1 + -1y)' equal to zero and attempt to solve:

Simplifying
-1 + -1y = 0

Solving
-1 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1y = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1y = 0 + 1
-1y = 0 + 1

Combine like terms: 0 + 1 = 1
-1y = 1

Divide each side by '-1'.
y = -1

Simplifying
y = -1
Subproblem 2
Set the factor '(12 + -1y)' equal to zero and attempt to solve:

Simplifying
12 + -1y = 0

Solving
12 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -1y = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -1y = 0 + -12
-1y = 0 + -12

Combine like terms: 0 + -12 = -12
-1y = -12

Divide each side by '-1'.
y = 12

Simplifying
y = 12
Solution
y = {-1, 12}