y(3-y)+5(y-7)=

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Solution for y(3-y)+5(y-7)= equation:


Simplifying
y(3 + -1y) + 5(y + -7) = 0
(3 * y + -1y * y) + 5(y + -7) = 0
(3y + -1y2) + 5(y + -7) = 0

Reorder the terms:
3y + -1y2 + 5(-7 + y) = 0
3y + -1y2 + (-7 * 5 + y * 5) = 0
3y + -1y2 + (-35 + 5y) = 0

Reorder the terms:
-35 + 3y + 5y + -1y2 = 0

Combine like terms: 3y + 5y = 8y
-35 + 8y + -1y2 = 0

Solving
-35 + 8y + -1y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
35 + -8y + y2 = 0

Move the constant term to the right:

Add '-35' to each side of the equation.
35 + -8y + -35 + y2 = 0 + -35

Reorder the terms:
35 + -35 + -8y + y2 = 0 + -35

Combine like terms: 35 + -35 = 0
0 + -8y + y2 = 0 + -35
-8y + y2 = 0 + -35

Combine like terms: 0 + -35 = -35
-8y + y2 = -35

The y term is -8y.  Take half its coefficient (-4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
-8y + 16 + y2 = -35 + 16

Reorder the terms:
16 + -8y + y2 = -35 + 16

Combine like terms: -35 + 16 = -19
16 + -8y + y2 = -19

Factor a perfect square on the left side:
(y + -4)(y + -4) = -19

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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