y(-9y+8)=0

Solution for y(-9y+8)=0 equation:

y(-9y+8)=0

We multiply parentheses

-9y^2+8y=0

a = -9; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-9)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-9}=\frac{-16}{-18}
=8/9
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-9}=\frac{0}{-18}
=0
$