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x=x2-10x+1
We move all terms to the left:
x-(x2-10x+1)=0
We add all the numbers together, and all the variables
-(+x^2-10x+1)+x=0
We get rid of parentheses
-x^2+10x+x-1=0
We add all the numbers together, and all the variables
-1x^2+11x-1=0
a = -1; b = 11; c = -1;
Δ = b2-4ac
Δ = 112-4·(-1)·(-1)
Δ = 117
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{117}=\sqrt{9*13}=\sqrt{9}*\sqrt{13}=3\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-3\sqrt{13}}{2*-1}=\frac{-11-3\sqrt{13}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+3\sqrt{13}}{2*-1}=\frac{-11+3\sqrt{13}}{-2} $
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