x=x2+12x-4

Solution for x=x2+12x-4 equation:

x=x2+12x-4

We move all terms to the left:

x-(x2+12x-4)=0

We add all the numbers together, and all the variables

-(+x^2+12x-4)+x=0

We get rid of parentheses

-x^2-12x+x+4=0

We add all the numbers together, and all the variables

-1x^2-11x+4=0

a = -1; b = -11; c = +4;
Δ = b2-4ac
Δ = -112-4·(-1)·4
Δ = 137
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{137}}{2*-1}=\frac{11-\sqrt{137}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{137}}{2*-1}=\frac{11+\sqrt{137}}{-2}
$