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x=7/2x+14
We move all terms to the left:
x-(7/2x+14)=0
Domain of the equation: 2x+14)!=0We get rid of parentheses
x∈R
x-7/2x-14=0
We multiply all the terms by the denominator
x*2x-14*2x-7=0
Wy multiply elements
2x^2-28x-7=0
a = 2; b = -28; c = -7;
Δ = b2-4ac
Δ = -282-4·2·(-7)
Δ = 840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{840}=\sqrt{4*210}=\sqrt{4}*\sqrt{210}=2\sqrt{210}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-2\sqrt{210}}{2*2}=\frac{28-2\sqrt{210}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+2\sqrt{210}}{2*2}=\frac{28+2\sqrt{210}}{4} $
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