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x=5x+2-(6x-3)
We move all terms to the left:
x-(5x+2-(6x-3))=0
We calculate terms in parentheses: -(5x+2-(6x-3)), so:We get rid of parentheses
5x+2-(6x-3)
determiningTheFunctionDomain 5x-(6x-3)+2
We get rid of parentheses
5x-6x+3+2
We add all the numbers together, and all the variables
-1x+5
Back to the equation:
-(-1x+5)
x+1x-5=0
We add all the numbers together, and all the variables
2x-5=0
We move all terms containing x to the left, all other terms to the right
2x=5
x=5/2
x=2+1/2
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