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x=4x^2-15x
We move all terms to the left:
x-(4x^2-15x)=0
We get rid of parentheses
-4x^2+x+15x=0
We add all the numbers together, and all the variables
-4x^2+16x=0
a = -4; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·(-4)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*-4}=\frac{-32}{-8} =+4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*-4}=\frac{0}{-8} =0 $
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