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x=43/43x-10
We move all terms to the left:
x-(43/43x-10)=0
Domain of the equation: 43x-10)!=0We get rid of parentheses
x∈R
x-43/43x+10=0
We multiply all the terms by the denominator
x*43x+10*43x-43=0
Wy multiply elements
43x^2+430x-43=0
a = 43; b = 430; c = -43;
Δ = b2-4ac
Δ = 4302-4·43·(-43)
Δ = 192296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{192296}=\sqrt{7396*26}=\sqrt{7396}*\sqrt{26}=86\sqrt{26}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(430)-86\sqrt{26}}{2*43}=\frac{-430-86\sqrt{26}}{86} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(430)+86\sqrt{26}}{2*43}=\frac{-430+86\sqrt{26}}{86} $
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