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x=4/5x+15=-5
We move all terms to the left:
x-(4/5x+15)=0
Domain of the equation: 5x+15)!=0We get rid of parentheses
x∈R
x-4/5x-15=0
We multiply all the terms by the denominator
x*5x-15*5x-4=0
Wy multiply elements
5x^2-75x-4=0
a = 5; b = -75; c = -4;
Δ = b2-4ac
Δ = -752-4·5·(-4)
Δ = 5705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-\sqrt{5705}}{2*5}=\frac{75-\sqrt{5705}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+\sqrt{5705}}{2*5}=\frac{75+\sqrt{5705}}{10} $
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