x=2x(x+8)

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Solution for x=2x(x+8) equation:



x=2x(x+8)
We move all terms to the left:
x-(2x(x+8))=0
We calculate terms in parentheses: -(2x(x+8)), so:
2x(x+8)
We multiply parentheses
2x^2+16x
Back to the equation:
-(2x^2+16x)
We get rid of parentheses
-2x^2+x-16x=0
We add all the numbers together, and all the variables
-2x^2-15x=0
a = -2; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·(-2)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*-2}=\frac{0}{-4} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*-2}=\frac{30}{-4} =-7+1/2 $

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