x=2(x+2)+3(x-2)

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Solution for x=2(x+2)+3(x-2) equation: 



x=2(x+2)+3(x-2)

We move all terms to the left:

x-(2(x+2)+3(x-2))=0



We calculate terms in parentheses: -(2(x+2)+3(x-2)), so:

2(x+2)+3(x-2)

We multiply parentheses

2x+3x+4-6

We add all the numbers together, and all the variables

5x-2

Back to the equation:

-(5x-2)



We get rid of parentheses

x-5x+2=0

We add all the numbers together, and all the variables

-4x+2=0

We move all terms containing x to the left, all other terms to the right

-4x=-2

x=-2/-4

x=1/2

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