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x=2(1/5)+7
We move all terms to the left:
x-(2(1/5)+7)=0
We add all the numbers together, and all the variables
x-(2(+1/5)+7)=0
We multiply all the terms by the denominator
x*5)+7)-(2(+1=0
Wy multiply elements
5x^2+1=0
a = 5; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·5·1
Δ = -20
Delta is less than zero, so there is no solution for the equation
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