x=19x2+13

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Solution for x=19x2+13 equation: 



x=19x^2+13

We move all terms to the left:

x-(19x^2+13)=0

We get rid of parentheses

-19x^2+x-13=0

a = -19; b = 1; c = -13;
Δ = b2-4ac
Δ = 12-4·(-19)·(-13)
Δ = -987
Delta is less than zero, so there is no solution for the equation

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