x=18-2x2

Solution for x=18-2x2 equation:

x=18-2x^2

We move all terms to the left:

x-(18-2x^2)=0

We get rid of parentheses

2x^2+x-18=0

a = 2; b = 1; c = -18;
Δ = b2-4ac
Δ = 12-4·2·(-18)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{145}}{2*2}=\frac{-1-\sqrt{145}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{145}}{2*2}=\frac{-1+\sqrt{145}}{4}
$