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x=10x^2+3
We move all terms to the left:
x-(10x^2+3)=0
We get rid of parentheses
-10x^2+x-3=0
a = -10; b = 1; c = -3;
Δ = b2-4ac
Δ = 12-4·(-10)·(-3)
Δ = -119
Delta is less than zero, so there is no solution for the equation
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