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x=1/6x+9
We move all terms to the left:
x-(1/6x+9)=0
Domain of the equation: 6x+9)!=0We get rid of parentheses
x∈R
x-1/6x-9=0
We multiply all the terms by the denominator
x*6x-9*6x-1=0
Wy multiply elements
6x^2-54x-1=0
a = 6; b = -54; c = -1;
Δ = b2-4ac
Δ = -542-4·6·(-1)
Δ = 2940
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2940}=\sqrt{196*15}=\sqrt{196}*\sqrt{15}=14\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-14\sqrt{15}}{2*6}=\frac{54-14\sqrt{15}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+14\sqrt{15}}{2*6}=\frac{54+14\sqrt{15}}{12} $
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