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x=1.7x^2+3x
We move all terms to the left:
x-(1.7x^2+3x)=0
We get rid of parentheses
-1.7x^2+x-3x=0
We add all the numbers together, and all the variables
-1.7x^2-2x=0
a = -1.7; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-1.7)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-1.7}=\frac{0}{-3.4} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-1.7}=\frac{4}{-3.4} =-1+0.6/3.4 $
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