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x=1.05/2x
We move all terms to the left:
x-(1.05/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-(+1.05/2x)=0
We get rid of parentheses
x-1.05/2x=0
We multiply all the terms by the denominator
x*2x-1.05=0
Wy multiply elements
2x^2-1.05=0
a = 2; b = 0; c = -1.05;
Δ = b2-4ac
Δ = 02-4·2·(-1.05)
Δ = 8.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{8.4}}{2*2}=\frac{0-\sqrt{8.4}}{4} =-\frac{\sqrt{}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{8.4}}{2*2}=\frac{0+\sqrt{8.4}}{4} =\frac{\sqrt{}}{4} $
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