x=-x2+8x+40

Solution for x=-x2+8x+40 equation:

x=-x2+8x+40

We move all terms to the left:

x-(-x2+8x+40)=0

We add all the numbers together, and all the variables

-(-1x^2+8x+40)+x=0

We get rid of parentheses

1x^2-8x+x-40=0

We add all the numbers together, and all the variables

x^2-7x-40=0

a = 1; b = -7; c = -40;
Δ = b2-4ac
Δ = -72-4·1·(-40)
Δ = 209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{209}}{2*1}=\frac{7-\sqrt{209}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{209}}{2*1}=\frac{7+\sqrt{209}}{2}
$