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x=-1/2x+513
We move all terms to the left:
x-(-1/2x+513)=0
Domain of the equation: 2x+513)!=0We get rid of parentheses
x∈R
x+1/2x-513=0
We multiply all the terms by the denominator
x*2x-513*2x+1=0
Wy multiply elements
2x^2-1026x+1=0
a = 2; b = -1026; c = +1;
Δ = b2-4ac
Δ = -10262-4·2·1
Δ = 1052668
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1052668}=\sqrt{4*263167}=\sqrt{4}*\sqrt{263167}=2\sqrt{263167}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1026)-2\sqrt{263167}}{2*2}=\frac{1026-2\sqrt{263167}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1026)+2\sqrt{263167}}{2*2}=\frac{1026+2\sqrt{263167}}{4} $
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