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x=-1/2x+10
We move all terms to the left:
x-(-1/2x+10)=0
Domain of the equation: 2x+10)!=0We get rid of parentheses
x∈R
x+1/2x-10=0
We multiply all the terms by the denominator
x*2x-10*2x+1=0
Wy multiply elements
2x^2-20x+1=0
a = 2; b = -20; c = +1;
Δ = b2-4ac
Δ = -202-4·2·1
Δ = 392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{392}=\sqrt{196*2}=\sqrt{196}*\sqrt{2}=14\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-14\sqrt{2}}{2*2}=\frac{20-14\sqrt{2}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+14\sqrt{2}}{2*2}=\frac{20+14\sqrt{2}}{4} $
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