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x=(x+1)(x+3)(x+5)-x(x+3)(x+5)
We move all terms to the left:
x-((x+1)(x+3)(x+5)-x(x+3)(x+5))=0
We multiply parentheses ..
-((+x^2+3x+x+3)(x+5)-x(x+3)(x+5))+x=0
We calculate terms in parentheses: -((+x^2+3x+x+3)(x+5)-x(x+3)(x+5)), so:
(+x^2+3x+x+3)(x+5)-x(x+3)(x+5)
We multiply parentheses ..
(+x^2+3x+x+3)(x+5)-x(+x^2+5x+3x+15)
We multiply parentheses
(+x^2+3x+x+3)(x+5)-x^3-5x^2-3x^2-15x
We do not support expression: x^3
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