x=(4x+20)+(3x-50)

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Solution for x=(4x+20)+(3x-50) equation: 



x=(4x+20)+(3x-50)

We move all terms to the left:

x-((4x+20)+(3x-50))=0



We calculate terms in parentheses: -((4x+20)+(3x-50)), so:

(4x+20)+(3x-50)

We get rid of parentheses

4x+3x+20-50

We add all the numbers together, and all the variables

7x-30

Back to the equation:

-(7x-30)



We get rid of parentheses

x-7x+30=0

We add all the numbers together, and all the variables

-6x+30=0

We move all terms containing x to the left, all other terms to the right

-6x=-30

x=-30/-6

x=+5

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