x=(3x-12)/(4x-2)

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Solution for x=(3x-12)/(4x-2) equation: 


D( x )

4*x-2 = 0

4*x-2 = 0

4*x-2 = 0

4*x-2 = 0 // + 2

4*x = 2 // : 4

x = 2/4

x = 1/2

x in (-oo:1/2) U (1/2:+oo)

x = (3*x-12)/(4*x-2) // - (3*x-12)/(4*x-2)

x-((3*x-12)/(4*x-2)) = 0

(-1*(3*x-12))/(4*x-2)+x = 0

(-1*(3*x-12))/(4*x-2)+(x*(4*x-2))/(4*x-2) = 0

x*(4*x-2)-1*(3*x-12) = 0

4*x^2-5*x+12 = 0

4*x^2-5*x+12 = 0

4*x^2-5*x+12 = 0

DELTA = (-5)^2-(4*4*12)

DELTA = -167

DELTA < 0

1 = 0

1/(4*x-2) = 0

1/(4*x-2) = 0 // * 4*x-2

1 = 0

x belongs to the empty set

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