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x=(3x+1)/4x
We move all terms to the left:
x-((3x+1)/4x)=0
Domain of the equation: 4x)!=0We multiply all the terms by the denominator
x!=0/1
x!=0
x∈R
x*4x)-((3x+1)=0
Wy multiply elements
4x^2=0
a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{8}=0$
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