x=(3/2)x+5

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Solution for x=(3/2)x+5 equation: 



x=(3/2)x+5

We move all terms to the left:

x-((3/2)x+5)=0



Domain of the equation: 2)x+5)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

x-((+3/2)x+5)=0

We multiply all the terms by the denominator


x*2)x+5)-((+3=0

Wy multiply elements

2x^2+3=0

a = 2; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·2·3
Δ = -24
Delta is less than zero, so there is no solution for the equation

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