x=(2x/3)+28

Solution for x=(2x/3)+28 equation:

x=(2x/3)+28

We move all terms to the left:

x-((2x/3)+28)=0

We add all the numbers together, and all the variables

x-((+2x/3)+28)=0

We multiply all the terms by the denominator


x*3)+28)-((+2x=0

We add all the numbers together, and all the variables

2x+x*3)+28)-((=0

Wy multiply elements

3x^2+2x=0

a = 3; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·3·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*3}=\frac{-4}{6}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*3}=\frac{0}{6}
=0
$