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x=(0.15x)(0.10-x)
We move all terms to the left:
x-((0.15x)(0.10-x))=0
We add all the numbers together, and all the variables
x-((+0.15x)(-1x+0.1))=0
We multiply parentheses ..
-((+0x^2+0x))+x=0
We calculate terms in parentheses: -((+0x^2+0x)), so:We add all the numbers together, and all the variables
(+0x^2+0x)
We get rid of parentheses
0x^2+0x
We add all the numbers together, and all the variables
x^2+x
Back to the equation:
-(x^2+x)
x-(x^2+x)=0
We get rid of parentheses
-x^2+x-x=0
We add all the numbers together, and all the variables
-1x^2=0
a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-2}=0$
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