x=(0.06-x)(0.06-x)

Solution for x=(0.06-x)(0.06-x) equation:

x=(0.06-x)(0.06-x)

We move all terms to the left:

x-((0.06-x)(0.06-x))=0

We add all the numbers together, and all the variables

x-((-1x+0.06)(-1x+0.06))=0

We multiply parentheses ..

-((+x^2-0.06x-0.06x+0.0036))+x=0


We calculate terms in parentheses: -((+x^2-0.06x-0.06x+0.0036)), so:

(+x^2-0.06x-0.06x+0.0036)

We get rid of parentheses

x^2-0.06x-0.06x+0.0036

We add all the numbers together, and all the variables

x^2-0.12x+0.0036

Back to the equation:

-(x^2-0.12x+0.0036)


We add all the numbers together, and all the variables

x-(x^2-0.12x+0.0036)=0

We get rid of parentheses

-x^2+x+0.12x-0.0036=0

We add all the numbers together, and all the variables

-1x^2+1.12x-0.0036=0

a = -1; b = 1.12; c = -0.0036;
Δ = b2-4ac
Δ = 1.122-4·(-1)·(-0.0036)
Δ = 1.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.12)-\sqrt{1.24}}{2*-1}=\frac{-1.12-\sqrt{1.24}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.12)+\sqrt{1.24}}{2*-1}=\frac{-1.12+\sqrt{1.24}}{-2}
$