x=((9*x)/5)+32

Solution for x=((9*x)/5)+32 equation:

x=((9x)/5)+32

We move all terms to the left:

x-(((9x)/5)+32)=0

We add all the numbers together, and all the variables

x-((+9x/5)+32)=0

We multiply all the terms by the denominator


x*5)+32)-((+9x=0

We add all the numbers together, and all the variables

9x+x*5)+32)-((=0

Wy multiply elements

5x^2+9x=0

a = 5; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·5·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*5}=\frac{-18}{10}
=-1+4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*5}=\frac{0}{10}
=0
$