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x3-7x^2+5=x(x2-1)+3x^2-2
We move all terms to the left:
x3-7x^2+5-(x(x2-1)+3x^2-2)=0
We add all the numbers together, and all the variables
-7x^2-(x(+x^2-1)+3x^2-2)+x3+5=0
We add all the numbers together, and all the variables
-7x^2+x^3-(x(+x^2-1)+3x^2-2)+5=0
We calculate terms in parentheses: -(x(+x^2-1)+3x^2-2), so:
x(+x^2-1)+3x^2-2
We add all the numbers together, and all the variables
3x^2+x(+x^2-1)-2
We multiply parentheses
3x^2+x^3-1x-2
We do not support expression: x^3
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