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x2=812
We move all terms to the left:
x2-(812)=0
We add all the numbers together, and all the variables
x^2-812=0
a = 1; b = 0; c = -812;
Δ = b2-4ac
Δ = 02-4·1·(-812)
Δ = 3248
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3248}=\sqrt{16*203}=\sqrt{16}*\sqrt{203}=4\sqrt{203}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{203}}{2*1}=\frac{0-4\sqrt{203}}{2} =-\frac{4\sqrt{203}}{2} =-2\sqrt{203} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{203}}{2*1}=\frac{0+4\sqrt{203}}{2} =\frac{4\sqrt{203}}{2} =2\sqrt{203} $
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