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x2=49289
We move all terms to the left:
x2-(49289)=0
We add all the numbers together, and all the variables
x^2-49289=0
a = 1; b = 0; c = -49289;
Δ = b2-4ac
Δ = 02-4·1·(-49289)
Δ = 197156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{197156}=\sqrt{4*49289}=\sqrt{4}*\sqrt{49289}=2\sqrt{49289}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{49289}}{2*1}=\frac{0-2\sqrt{49289}}{2} =-\frac{2\sqrt{49289}}{2} =-\sqrt{49289} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{49289}}{2*1}=\frac{0+2\sqrt{49289}}{2} =\frac{2\sqrt{49289}}{2} =\sqrt{49289} $
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