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x2=2x/5=9
We move all terms to the left:
x2-(2x/5)=0
We add all the numbers together, and all the variables
x2-(+2x/5)=0
We add all the numbers together, and all the variables
x^2-(+2x/5)=0
We get rid of parentheses
x^2-2x/5=0
We multiply all the terms by the denominator
x^2*5-2x=0
Wy multiply elements
5x^2-2x=0
a = 5; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·5·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*5}=\frac{0}{10} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*5}=\frac{4}{10} =2/5 $
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