x2=242+322

Solution for x2=242+322 equation:

x2=242+322

We move all terms to the left:

x2-(242+322)=0

We add all the numbers together, and all the variables

x2-564=0

We add all the numbers together, and all the variables

x^2-564=0

a = 1; b = 0; c = -564;
Δ = b2-4ac
Δ = 02-4·1·(-564)
Δ = 2256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2256}=\sqrt{16*141}=\sqrt{16}*\sqrt{141}=4\sqrt{141}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{141}}{2*1}=\frac{0-4\sqrt{141}}{2}
=-\frac{4\sqrt{141}}{2}
=-2\sqrt{141}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{141}}{2*1}=\frac{0+4\sqrt{141}}{2}
=\frac{4\sqrt{141}}{2}
=2\sqrt{141}
$