x2=-9x+20-0

Solution for x2=-9x+20-0 equation:

x2=-9x+20-0

We move all terms to the left:

x2-(-9x+20-0)=0

We add all the numbers together, and all the variables

x2-(-9x+20)=0

We add all the numbers together, and all the variables

x^2-(-9x+20)=0

We get rid of parentheses

x^2+9x-20=0

a = 1; b = 9; c = -20;
Δ = b2-4ac
Δ = 92-4·1·(-20)
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{161}}{2*1}=\frac{-9-\sqrt{161}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{161}}{2*1}=\frac{-9+\sqrt{161}}{2}
$